If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel.
Given: M and N are midpoints of chords AB and CD respectively.
MN passes through the centre of the circle O
To prove: Chord AB and Chord CD are parallel
Construction: Join B and C.
Proof:
M = N = 90° (Segment joining the midpoint of the chord to the centre)
Consider, DOMB and DONC
BOM = CON (Vertically opposite angles)
OB = OC (Radii of the same circle)
OMB = ONC (90° each)
OMB ONC (AAS congruence)
OBM = OCN (CPCT)
ABC = BCD
We can see that ABC and BCD are alternate angles of the chords AB and CD with BC as transversal.
Hence, chord AB || chord CD.