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  • If E and F are events such that P(E) = 1/4 , P(F) = 1/2 and P(E and F) = 1/8 , find (i) P(E or F)

15.(i)   If E and F are events such that   P(E)=\frac{1}{4},   P(F)=\frac{1}{2}   and    P(E\hspace{1mm}and\hspace{1mm}F)=\frac{1}{8},  find (i)  P(E or F) 

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Given, P(E)=\frac{1}{4},   P(F)=\frac{1}{2}   and    P(E\hspace{1mm}and\hspace{1mm}F)=\frac{1}{8}

To find : P(E or F) = P(E \cup F)

We know,

  P(A \cup B) = P(A)+ P(B) - P(A \cap B)

\implies P(E \cup F) = \frac{1}{4}+\frac{1}{2} -\frac{1}{8} = \frac{2+4-1}{8}

 = \frac{5}{8}
Therefore,  P(E \cup F) = \frac{5}{8}

Posted by

HARSH KANKARIA

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