Q2.     If h = 10 cm, c = 6 cm, b = 12 cm, d = 4 cm, find the values of each of its parts separetely and add to find the area WXYZ.            Verify it by putting the values of h, a and b in the expression \frac{h(a+b)}{2}.

Answers (1)

Area of trapezium WXYZ = Area of traingle with base'c'+area of rectangle +area of triangle with base 'd'

                                          =\left ( \frac{1}{2}\times c\times h \right )+\left ( b\times h \right )+\left ( \frac{1}{2}\times d\times h \right )

                                         =\left ( \frac{1}{2}\times 6\times 10 \right )+\left ( 12\times 10 \right )+\left ( \frac{1}{2}\times 4\times 10 \right )

                                        =\left ( 30 \right )+\left ( 120 \right )+\left ( 20 \right )

                                       =170 cm^{2}

the area WXYZ by  the expression 

.\frac{h(a+b)}{2}

=\frac{10 \left ( 22+12 \right )}{2}

=\frac{10 \left ( 34 \right )}{2}

=10\times 17

=170 cm^{2}

Hence,we can conclude area from given expression and calculated area is equal.

 

 

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