# Q2.     If h = 10 cm, c = 6 cm, b = 12 cm, d = 4 cm, find the values of each of its parts separetely and add to find the area WXYZ.            Verify it by putting the values of h, a and b in the expression $\frac{h(a+b)}{2}$.

Area of trapezium WXYZ = Area of traingle with base'c'+area of rectangle +area of triangle with base 'd'

$=\left ( \frac{1}{2}\times c\times h \right )+\left ( b\times h \right )+\left ( \frac{1}{2}\times d\times h \right )$

$=\left ( \frac{1}{2}\times 6\times 10 \right )+\left ( 12\times 10 \right )+\left ( \frac{1}{2}\times 4\times 10 \right )$

$=\left ( 30 \right )+\left ( 120 \right )+\left ( 20 \right )$

$=170$ $cm^{2}$

the area WXYZ by  the expression

.$\frac{h(a+b)}{2}$

$=\frac{10 \left ( 22+12 \right )}{2}$

$=\frac{10 \left ( 34 \right )}{2}$

$=10\times 17$

$=170 cm^{2}$

Hence,we can conclude area from given expression and calculated area is equal.

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