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Q. 3. If $P(A)=0.8,P(B)=0.5$ and $P(B\mid A)=0.4,$ find

(i) $P(A\cap B)$

Answers (1)

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It is given that P(A)=0.8, P(B)=0.5 and P(B|A)=0.4

$P ( B | A ) = \frac{p(A\cap B)}{P(A)}$

$0.4 = \frac{p(A\cap B)} {0.8}$

$p(A\cap B) = 0.4 \times 0.8$

$p(A\cap B) = 0.32$

Posted by

seema garhwal

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