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Q. 3. If $P(A)=0.8,P(B)=0.5$ and $P(B\mid A)=0.4,$ find

(iii) $P(A\cup B)$

Answers (1)

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It is given that $P(A)=0.8,P(B)=0.5$

$P(A\cap B)=0.32$

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$P(A\cup B)=0.8+0.5-0.32$

$P(A\cup B)=1.3-0.32$

$P(A\cup B)=0.98$

Posted by

seema garhwal

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