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  • If the speed of light is 3.0 × 10 8 m s^ –1 , calculate the distance covered by light in 2.00 ns.

1.22    If the speed of light is 3.0 \times 10^8 m s^{-1} , calculate the distance covered by light in 2.00 ns.

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Given the speed of light to be 3.0 \times 10^8 m s^{-1}, so the distance covered by light in 2.00 ns. will be:

Distance = Speed\times Time

Distance = (3.0\times10^{8}ms^{-1})\times(2.00\times10^{-9}sec) = 6.00\times10^{-1}m = 0.600m

Therefore, the light will travel 0.600 metres in 2 nano seconds.

Posted by

Divya Prakash Singh

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