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# In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (b) two tickets

4.(b)  In a certain lottery  $\small 10,000$  tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (b) two tickets

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Given, Total number of tickets sold = 10,000

Number of prizes awarded = 10

(b) If two tickets are bought:

Number of tickets not awarded = 10000 - 10 = 9990

$\therefore$ P(not getting a prize) = $\frac{^{9990}\textrm{C}_{2}}{^{10000}\textrm{C}_{2}}$

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