Q (5) In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of the minor arc of the chord.
Given:- radius (r)of circle =
length of chord = 20 cm
We know that
(r = 20cm , l = ? , = ?)
Now,
AB is the chord of length 20cm and OA and OB are radii of circle 20 cm each
The angle subtended by OA and OB at the centre =
OA = OB = AB
OAB is an equilateral triangle
So, each angle equilateral is
Now, we have and r
So,
the length of the minor arc of the chord (l) = cm