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  • In Fig. 8.13, find tan P - cot R.

2.     In Fig. 8.13, find \tan P - \cot R.

             

Answers (1)

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We have, \DeltaPQR is a right-angled triangle, lengths of PQ and PR are 12 cm and 13 cm respectively.
So, by using Pythagoras theorem,
QR = \sqrt{13^2-12^2}
QR = \sqrt{169-144}
QR = \sqrt{25} = 5\ cm

Now, According to the question,


\tan P -\cot R = \frac{RQ}{QP}-\frac{QR}{PQ}
                              = \frac{5}{12} - \frac{5}{12} = 0

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manish

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