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In the Solvay process, can we obtain sodium carbonate directly by treating the solution containing (NH_{4})_{2}CO_{3} with sodium chloride? Explain.

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(NH_{4})_{2}CO_{3} reacts with NaCl to get Na_{2}CO_{3} and NH_{4}Cl. Both the products are highly soluble in water and equilibrium can not shift in forward direction. That is why Na_{2}CO_{3} can  not be prepared directly.

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