In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH_{4}Cl with Ca(OH)_{2}. The by-product obtained in this process is
(i) CaCl_{2}
(ii) NaCl
(iii) NaOH
(iv) NaHCO_{3}

Answers (1)

The answer is the option (i) CaCl_{2}

On treating NH_{4}Cl with Ca(OH)_{2} , CaCl_{2} is formed as a by product

2NH_{4} Cl+CaOH_{2} \rightarrow 2NH_{3}+2H_{2}O+CaCl_{2}

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