In triangles ABC and DEF, AB = FD and A =
D. The two triangles will be congruent by SAS axiom if
(A) BC = EF
(B) AC = DE
(C) AC = EF
(D) BC = DE
SAS congruent axiom says that the two triangles are congruent if two sides and the included angle of one triangle are equal to the corresponding two sides and the included angle of the other triangle.
AB = FD and
A =
D (given)
Then to be congruent by SAS axiom
AC = DE
Hence option (B) is correct.