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In triangles ABC and DEF, AB = FD and \angleA = \angleD. The two triangles will be congruent by SAS axiom if

(A) BC = EF

(B) AC = DE

(C) AC = EF

(D) BC = DE

Answers (3)

SAS congruent axiom says that the two triangles are congruent if two sides and the included angle of one triangle are equal to the corresponding two sides and the included angle of the other triangle.

\because AB = FD and \angleA = \angleD (given)

Then to be congruent by SAS axiom

AC = DE

Hence option (B) is correct.

Posted by

infoexpert24

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Answer B

Posted by

DIVYANSH SLATHIA

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Bc=ef=

Posted by

Siba Naryan Nayak

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