Match the species given in Column I with the hybridisation given in Column II.

Column I

Column II

(i) Boron in [B(OH)_{4}]^-

(a) sp^2

(ii) Aluminium in [Al(H_{2}O)_{6}]^{3+}

(b) sp^{3}

(iii) Boron in B_{2}H_{6}

(c) sp^{3}d^{2}

(iv) Carbon in Buckminsterfullerene

 

(v) Silicon in SiO_{4}^{4-}

 

(vi) Germanium in [GeCl_{6}]^{2-}


 

 

Answers (1)

(i →b) 

  • Boron in [B(OH)_{4}]^{-} is sp^{3}  and is the central atom.

(ii→ c);

  • Aluminium in [Al(H_{2}O)_{6}]^{3+} is sp^{3}d^{2} hybridized and has octahedral geometry.

(iii → b);

  • Boron in B_{2}H_{6} is sp^{3}, and the 4 hybrids have the same geometric configuration except one.

(iv→ a);

  • Carbon in Buckminsterfullerene sp^2  is hybridized. Each atom forms a sigma bond with 3 others.

(v →b);

  • Silicon in SiO_{4}^{4-} is sp^{3} and has tetrahedral geometry.

(vi→ c)

  • Germanium in [GeCl_{6}]^{2-} is sp^{3}d^{2}  and has octahedral geometry.

 

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