Match the species given in Column I with the properties mentioned in Column II.

Column I

Column II

(i) BF_4^{-}

(a) Oxidation state of central atom is +4

(ii) AlCl_{3}

(b) Strong oxidising agent

(iii) SnO

(c) Lewis acid

(iv) PbO_{2}

(d) Can be further oxidised

 

(e) Tetrahedral shape

Answers (1)

(i→e);
BF_4^{-}: Tetrahedral shape

Due to the sp^3 hybridization, it has regular geometry with no lone pairs but 4 pairs that have bonded.

(ii → c);
Al_{3}Cl_{3}: Lewis acid

The octet of is incomplete and thus is an electron acceptor making it a Lewis acid.

(iii —> d);
SnO: Can be further oxidized

 Sn^{2+} can lose 2 more electrons to form a +4 oxidation state.

(iv →a, b)
PbO_{2} :  Oxidation state of the central atom is +4, Strong oxidizing agent

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