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Show that in a cubic close packed structure, eight tetrahedral voids are present per unit cell.

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In ccp, each unit cell consists of eight cubic components and the number of atoms per unit cell is given by

Nc*contribution+Nf*contribution  

=8\times \frac{1}{}8+6\times \frac{1}{2}=4
 
The tetrahedral voids are positioned at the centre of cubic cell.

In cubic close packing number of tetrahedral voids per unit cell = 8\times 1=8

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