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The bob A of a pendulum released from horizontal to the vertical hits another bob B of the same mass at rest on a table as shown in the figure. If the length of the pendulum is 1 m, calculate

a) the height to which bob A will rise after collision

b) the speed with which bob B starts moving.

Neglect the size of the bobs and assume the collision to be elastic.

Answers (1)

a) when the bob which is in motion collides with the bob at rest, it transfers the momentum and comes to a state of rest. When the position of B is reached by bob A, kinetic energy is obtained by A as a result of the conversion of potential energy. This happens as the momentum is transferred due to elastic collision. So, bob A will not rise.

b)

PE at A1 is equal to kinetic energy at A2 which is equal to kinetic energy at B1

So,

\frac{1}{2}mv^{2} = mgh

V_{b} = \sqrt{2g\times 1} = 4.42 m/s

 

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