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4    The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

    

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 The diagonal of a quadrilateral shaped field is 24 m 

the perpendiculars are 8 m and 13 m. 

the area of the field =

\frac{1}{2}\times d\times (h1+h2)

=\frac{1}{2}\times 24\times (13+8)

=12\times 21

=252 m^{2}

Posted by

seema garhwal

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