The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m^{2} is  4.

Answers (1)

Area of 1 tile = 

\frac{1}{2}\times product\, of\, diagonals

=\frac{1}{2}\times45\times 30

=675 cm^{2}

Area of 3000 tiles = 

=675 \times 3000

= 202.5 m^{2}

Total cost of polishing =

= 202.5\times 4

= Rs 810

 

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