The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)_{4}]^{-} and the geometry of the complex are respectively
(i)sp^{3} , tetrahedral
(ii)sp^{3}, square planar
(iii) sp^{3}d^{2}, octahedral
(iv) dsp^{2} , square planar

Answers (1)

The answer is the option (i)sp^{3} , tetrahedral

Boron in the excited state has 2s orbitals which are not paired and one electron which is in the p-orbital. In hybridization, the sp^{3} hybridization is formed, and tetrahedral geometry is observed.

Electronic configuration of boron; 1s^{2}2s^{2}2px^{1}2p^{0}y2p^{^{\circ}}z

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