The most commonly used reducing agent is
(i) AlCl_3
(ii) PbCl_2
(iii) SnCl_4
(iv) SnCl_{2}

Answers (1)

The answer is the option (iv) SnCl_{2}

Sn has the oxidation state of +4 and is more stable than the other oxidation states. Thus it is easily oxidized to Sn^{4+}  and becomes a reducing agent.

SnCl_{2} + 2Cl \rightarrow SnCl_{4} + 2e^{-}

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