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Q. 5: The probability that a bulb produced by a factory will fuse after $150$ days of use is $0.05$ . Find the probability that, out of $5$ such bulbs

(iv) at least one will fuse after $150$ days of use.

Answers (1)

best_answer

Let X represent the number of bulbs that will fuse after $150$ days of use. Trials = 5

$P=0.005$

$q=1-0.005=1-0.005=0.95$

X has a binomial distribution with n = 5.

$\therefore \, \, \, \, P(X=x)=^nC_x.q^{n-x}.p^x$

$P(X=x)=^5C_x.$ $(0.95)^{5-x} . (0.05)^{x}$

Put $X\geq 1$ ,

$P(X\geq 1)=1-P(X< 1)$

$P(X\geq 1)=1-P(X=0)$

$=1-^5C_0.$ $(0.95)^{5} . (0.05)^{0}$

$=1-(0.95)^{5}$

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seema garhwal

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