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  • The work function for caesium atom is 1.9 eV. Calculate (a) the threshold wavelength

2.51 The work function for caesium atom is 1.9 eV. Calculate (a) the threshold wavelength

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Given the work function for the Caesium atom is 1.9\ eV.

i.e., W_{o} = h\nu_{o} = \frac{hc}{\lambda_{o}}   Or   \lambda_{o} = \frac{hc}{W_{o}}

As 1\ eV = 1.602\times10^{-19}J

\therefore 1.9\ eV =1.9\times1.602\times10^{-19}J =3.0438\times10^{-19}J

\lambda_{o} = \frac{(6.626\times10^{-34}Js)(3.0\times10^8)J}{3.0438\times10^{-19}J} =6.5306\times 10^{-7} m

Therefore, the threshold wavelength is 6.53× 10-7 m.

Posted by

Divya Prakash Singh

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