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  • There are two sources of light, each emitting with a power of 100 W. One emits X-rays of wavelength 1nm and the other visible light at 500 nm. Find the ratio of a number of photons of X-rays to the photons of visible light of the given wavelength?

There are two sources of light, each emitting with a power of 100 W. One emits X-rays of wavelength 1nm and the other visible light at 500 nm. Find the ratio of a number of photons of X-rays to the photons of visible light of the given wavelength?

Answers (1)

Let EX and EV be the energies given by one photon in X-rays and

visible rays respectively.

  Then EX=hvX  and  EV=hvV

  Let nX and nV be the number of photons from x-rays and visible

 light are of equal energies and they emit 100 W power. 

n_{X}hv_{X}=n_{V}hv_{V}\\ \frac{n_{X}}{n_{V}}=\frac{v_{V}}{v_{X}}=\frac{\lambda_{X}}{\lambda_{V}}\\ \frac{n_{X}}{n_{V}}=\frac{1}{500}\; \; \; n_{X}:n_{V}=1:500

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