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  • Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?

Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?

Answers (1)

The work-energy theorem states that the change in the kinetic energy is equal to the work done by the body. So, we can say that KE = WD.

It is given thatKE_{1} = KE_{2}

Hence, WD_{1} = WD_{2}

So, F_{1}S_{1} = F_{2}S_{2}

Since F1 and F2 are equal, S_{1} and S_{2} are also equal.

Hence, irrespective of the mass of the bodies, they travel an equal amount of distance/displacement.

Posted by

infoexpert24

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