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Two pendulums with identical bobs and lengths are suspended from a common support such that in rest position the two bobs are in common. One of the bobs is released after being displaced by 10o so that it collides elastically head-on with the other bob.

a) describe the motion of two bobs

b) draw a graph showing variation in energy of either pendulum with time for0 \leq t \leq 2Twhere T is the period of each pendulum.

Answers (1)

PE(A) = 0, PE(B) = E, KE(A) = KE(B) = 0

These are the initial values when the bobs are at rest. After this, the bobs are released.

t=\frac{T}{4}

when B reaches A, both the bobs collide elastically,

so, KE(A) = 0, KE(B) = E, PE(A) = PE(B)=0

t=\frac{2T}{4}

A will reach at the highest point or at maximum height. And, B is at its lowest point

KE(A) = 0, KE(B) = 0, PE(A) =E, PE(B)=0

 

t=\frac{3T}{4}

bob A hits bob B. Bob A comes to rest and Bob B starts moving

KE(A) = 0, KE(B) = E, PE(A) =0, PE(B)=0

Ea = 0, Eb = E

 

t=\frac{4T}{4}

B will reach at the highest point or at maximum height. And, A is at its lowest point

KE(A) = 0, KE(B) = 0, PE(A) =0, PE(B)=E

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