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Two pendulums with identical bobs and lengths are suspended from a common support such that in the rest position the two bobs are in common. One of the bobs is released after being displaced by 10o so that it collides elastically head-on with the other bob.

a) describe the motion of two bobs

b) draw a graph of the showing variation in energy of either pendulum with time for 0 \leq t \leq 2Twhere T is the period of each pendulum.

Answers (1)

PE(A) = 0, PE(B) = E, KE(A) = KE(B) = 0

These are the initial values when the bobs are at rest. After this, the bobs are released.

t=\frac{T}{4}

when B reaches A, both the bobs collide elastically,

so, KE(A) = 0, KE(B) = E, PE(A) = PE(B)=0

t=\frac{2T}{4}

A will reach the highest point or at maximum height. And, B is at its lowest point

KE(A) = 0, KE(B) = 0, PE(A) =E, PE(B)=0

 

t=\frac{3T}{4}

Bob A hits Bob B. Bob A comes to rest and Bob B starts moving

KE(A) = 0, KE(B) = E, PE(A) =0, PE(B)=0

Ea = 0, Eb = E

 

t=\frac{4T}{4}

B will reach the highest point or at maximum height. And, A is at its lowest point

KE(A) = 0, KE(B) = 0, PE(A) =0, PE(B)=E

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