# 1. We know that parallelogram is also a quadrilateral. Let us also split such a quadrilateral into two triangles, find their areas  and hence that of the parallelogram. Does this agree with the formula that you know already? (Fig 11.12)

S seema garhwal

$Area \:of \:quadrilateral \:ABCD = Area \:of( \bigtriangleup ABD \:+\:\bigtriangleup BCD)$

$=\left ( \frac{1}{2}\times b\times h \right )+\left ( \frac{1}{2}\times b\times h \right )$

$=bh$

This agree with the formula that we know already.

Exams
Articles
Questions