Which of the following pair is expected to have the same bond order?
(i) O_{2},N_{2}
(ii) O{_{2}}^{+},N{_{2}}^{-}
(iii) O{_{2}}^{-},N{_{2}}^{+}
(iv) O{_{2}}^{-},N{_{2}}^{-}

Answers (1)

The answer is the option (ii) O{_{2}}^{+},N{_{2}}^{-};  because the Isoelectronic species have a similar bond order.

Option I-O_{2} has 16 electrons and N2 has 14 electrons.

Option II - Both O_{2}^{+} and N_{2}^{-} has 15 electrons.

Option III - O_{2}^{-} has 17 electrons and N_{2}^{+} has 13 electrons.


Option IV - O_{2}^{-}has 17 electrons and N_{2}^{-} has 15 electrons

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