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  • Which of the following options represents the correct bond order : (i) O{_{2}}^{-}>O_{2}>O{_{2}}^{+} (ii) O{_{2}}^{-}<O_{2}<O{_{2}}^{+}

Which of the following options represents the correct bond order :
(i) O{_{2}}^{-}>O_{2}>O{_{2}}^{+}
(ii) O{_{2}}^{-}<O_{2}<O{_{2}}^{+}
(iii) O{_{2}}^{-}>O_{2}<O{_{2}}^{+}
(iv) O{_{2}}^{-}<O_{2}>O{_{2}}^{+}

Answers (1)

The answer is the option (ii) O{_{2}}^{-}<O_{2}<O{_{2}}^{+}

Explanation:  Nb electrons > Na electrons as well as, it depends on the bond order.

B.O. = ½(Nb – Na)

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