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Match the species in Column I with the type of hybrid orbitals in Column II.

Column I

Column II

(i) $SF_{4}$

(a) sp³d²

(ii) $if_{5}$

(b) d²sp³

(iii) $NO{_{2}}^{+}$

(c) sp³ d

(iv) $NH_{4}^{+}$

(d) sp³

(e) sp

Answers (1)

(i)→ (c); (ii) →(a); (iii) →(e); (iv) →(d)

Explanation:

Column I	Column II
SF₄	S is surrounded by 4 bond pairs and 1 lone pair (sp³d hybridization)
IF₅	I is surrounded by 5 bond pairs and 1 lone pair (sp³d² hybridization)
NO₂⁺	N has 2 bond pairs and no lone pair (sp hybridization)
NH₄⁺	N has 4 bond pairs and no lone pair (sp³hybridization)

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