q3)workout the following divisions

iv)  

9 x ^2 y^2 ( 3z -24 ) \div 27 xy ( z-8 )

Answers (1)

We have,
           9x^{2}y^{2}(3z-24) = 9x^{2}y^{2} \times 3(z-8) = 27x^{2}y^{2}(z-8)

\therefore \frac{9x^{2}y^{2}(3z-24)}{27xy(z-8)} = \frac{27x^{2}y^{2}(z-8)}{27xy(z-8)} = xy

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