The correct match of compounds with their functions is - (i —> b), (ii —> d), (iii —> a), (iv —> e), (v —> c)
(i) Antagonist drugs are used for inhibiting the functioning of specific enzyme receptors. For example, to block the dopamine receptors by receptor antagonism, the drug used is of the dopamine antagonist...

Given : Rhombus with diagonals length = 4 cm, 6 cm
Steps of Construction :
1. Draw a line AB = 4 cm
2. Bisect the AB using another line EF which intersects it at point X
E X F is perpendicular to AB
3. As center X mark an arc of 3 cm as the radius on XF and XE which intersects at C and D...

The detergent components and their use are matches as follows -(i —> c), (ii —> d), (iii —> b), (iv —> a)
(i) The detergents used in hair shampoos/conditioners are cationic, containing quaternary ammonium salts of amines along with chlorides, bromides or acetates, etc. Examples of cationic detergent are cetyltrimethyl ammonium bromide.
(ii) Toothpaste contains anionic detergents for e.g.,...

The correct match of the structure with their type of detergent are - (i —> c), (ii —> d), (iii —> b), (iv -> a)

Given : An equilateral triangle with Altitude : 3.2 cm
Steps of Construction :
1. Draw a line XY and take a point D on it .
2. Draw line DE with angle at D.
3. Cut the line DE with arc of radius 3.2 cm at point A
4. Make an angle of at A which cuts XY at B.
5. Now find the length...

Given : Side = 3.5 cm, sum of other side and hypotenuse = 5.5 cm
Steps Construction :
Draw line BC = 3.5 cm
Draw line BE with angle at B.
3. Cut BE by 5.5 cm radius arc at D.
4. Join DC
5. Bisect DC which intersects BD at point A
6. Join AC
ABC is the required triangle.
...

Given : QR = 3cm, , QP – PR = 2 cm.
Steps of Construction :
1. Draw line QR = 3 cm
2. Draw line QB with angle at Q.
3. Make an arc on QB of 2cm radius intersecting at A
4. Join AR
5. Bisect AR and extend it so it intersects QB at P
6. Join...

Steps of Construction :
Draw a line PQ = 10.4 cm
Draw line PR with angle at P.
Draw line QS with angle at Q.
3. Bisect and and then let their bisectors meet at point A
4. Bisect line AQ and AP which meets PQ at C and B respectively.
5. Join A with B and C.
ABC is the required...

The right match of the above options are - (i ->b), (ii —» a), (iii —» d), (iv —> c)
(i) Soap chips – as the name suggests, are formed spreading and cooling the melted soap and then cutting it into small pieces. ...

Match the medicines given in Column I with their use given in Column II.

Column I |
Column II |

(i) Ranitidin |
(a) Tranquilizer |

(ii) Furacine | (b) Antibiotic |

(iii) Phenelzine | (c) Antihistamine |

(iv) Chloramphenicol | (d) Antiseptic |

(e) Antifertility drug |

The correct match of the medicines and their role is- (i —> c), (ii —» d), (iii —» a), (iv —» b)
(i) Ranitidine – It is used to inhibit the histamine interaction with enzyme receptors in the stomach wall. It directly regulates the production of hydrochloric acid and...

Given : Side = 3.4 cm, Angle =
Steps of Construction :
Draw a line AB = 3.4 cm
Draw lines AF and BE with angles at A and B respectively.
3. Draw arcs with center A and B of radius 3.4 cm which intersect AF at D and BE at C
4. Join DC
ABCD is a rhombus of side 3.4 cm and of angle

Given : adjacent sides are of lengths 5 cm and 3.5 cm.
Steps of Construction :
Draw line AB = 5 cm
Draw lines AD and BC with 90° angles at A and B respectively.
3. Mark arc of radius 3.5 cm on AD, BC which intersect AD at E and BC at F.
4. Join EF
ABFE is required rectangle.

Given : side = 3 cm
Steps of Construction :
We know that in square each angle is of and all sides are equal.
1. Draw AB = 3 cm
2. Draw lines AE and BF with angles at A and B respectively.
3. With centers A and B, cut line AE and BF with arcs of radius 3 cm at points C and D respectively.
...

Given : BC = 5 cm, , AC + AB = 7.5 cm
Steps of Construction:
1. Draw a line BC = 5 cm
2. Draw an angle of at B
3. Mark an arc on line of angle 60° with radius 7.5 cm at point D.
4. Join DC
5. Bisect DC which intersects BD at point A
6. Join AC
DABC...

Steps of Construction :
1. Draw a line AB = 4.8 cm
2. With A as center, mark an arc of 3.6 cm radius and with B as center, cut the arc with 3 cm radius at point C.
3. Draw the line AC and BC which are of length 3.6 cm and 3 cm respectively.
4. With A as center, draw an arc which cuts AB and AC at point F, E...

Steps of Construction :
1. Draw an angle with protractor
2. Taking A as the centre, draw a semi-circle with any radius which cuts AB at point G
And cuts AC at point F.
3. Taking F and G as centres, draw arcs which intersect each other at D.
4. Draw AE passing through...

Steps of Construction:
1. Draw a line, AB = 4 cm
2. Take A and B as centers and draw arcs which intersect AB at E and H respectively.
3. Take E as center and draw an arc of same radius as arc of A, B, which intersects the previous arc at F. Then, take the same radius and center F and make an arc which intersects at G.
4. Perform step 3 for H, as a...

Steps of Construction:
1. Make an angle of by using a protractor
2. Take B as the centre and draw an arc which intersects BC and BA at E and D respectively.
3. Take D and E as centres and draw arcs (without changing the span of the compass) such that they intersect each other at point F.
4. Draw a line BG which passes through F.
Angles...

Given : , AB + BC + AC = 12 cm.
We know that the sum of interior angles of a triangle is
Sum of two angles is less than
Also, sum of all the sides is given as 12 cm, which does not contradict any property of a triangle.
Hence this type of triangle can be constructed.
Therefore the given statement is True.

Answer
False
Solution
Given : , AB + BC + AC = 10 cm.
We know that the sum of interior angles of a triangle is 180°.
But here
The sum of two angles is greater than which is not possible.
Hence, this type of triangle can’t be constructed.
Therefore the given statement is False.

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