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Q4.    Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method :

                (v) The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

Let  be the length of the rectangle and  be the width, Now, According to the question, Also, By Cross multiplication method, Hence the length and width of the rectangle are 17 unit and 9 unit respectively.

Q4.    Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method :

                (iv) Places A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at different speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What are the speeds of the two cars?

Let the speed of the first car is x and the speed of the second car is y. Let's solve this problem by using relative motion concept, the relative speed when they are going in the same direction= x - y  the relative speed when they are going in the opposite direction= x + y The given relative distance between them = 100 km. Now, As we know, Relative distance = Relative speed * time . So,...

Q4.    Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method :

                (iii) Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks. How many questions were there in the test?

Let the number of right answer and wrong answer be x and y respectively  Now, According to the question, And Now, subtracting (2) from (1) we get, Putting this value in (1) Hence the total number of question is 

Q4.    Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method :

                (ii) A fraction becomes \frac{1}{3} when 1 is subtracted from the numerator and it becomes \frac{1}{4} when 8 is added to its denominator. Find the fraction.

Let numerator of a fraction be x and the denominator is y. Now, According to the question, Also, Now, Subtracting (1) from (2) we get, Putting this value in (2) we get, Hence, the fraction is  .

Q4.    Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method :

                (i) A part of monthly hostel charges is fixed and the remaining depends on the number of days one has taken food in the mess. When a student A takes food for 20 days she has to pay Rs 1000 as hostel charges whereas a student B, who takes food for 26 days, pays Rs 1180 as hostel charges. Find the fixed charges and the cost of food per day.

Let the fixed charge be x and the cost of food per day is y, Now, According to the question  Also Now subtracting (1) from (2),  Putting this value in (1) Hence, the Fixed charge is Rs 400 and the cost of food per day is Rs 30.

Q3.    Solve the following pair of linear equations by the substitution and cross-multiplication methods :
                \\8x + 5y = 9 \\3x + 2y = 4

Given the equations  By Substitution Method, From (1) we have  Substituting this in (2),  Substituting this in (3) Hence . By Cross Multiplication Method

Q2.    (ii) For which value of k will the following pair of linear equations have no solution?

                \\3x + y = 1 \\(2k - 1) x + (k - 1) y = 2k + 1

Given, the equations, As we know, the condition for equations   to have no solution is So, Comparing these equations with, , we get From here we get, Hence, the value of K is 2.

Q2.    (i) For which values of a and b does the following pair of linear equations have an infinite number of solutions?
                \\2x + 3y = 7 \\(a - b) x + (a + b) y = 3a + b - 2

Given     equations, As we know, the condition for equations   to have an infinite solution is So, Comparing these equations with, , we get From here we get, Also, Now, Subtracting (2) from (1) we get Substituting this value in (1)  Hence, .

Q1.    Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.

                (iv)    \\x - 3y -7 = 0\\ 3x -3y -15 =0

Given the equations, Comparing these equations with , we get As we can see,  Hence, the pair of equations has exactly one solution. By Cross multiplication method,

Q1.    Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.

                (iii)    \\3x -5 y = 20\\ 6x - 10y = 40

Given The equations, Comparing these equations with , we get As we can see,  Hence, the pair of equations has infinitely many solutions.  

Q1.    Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.

                (ii)    \\2x + y = 5 \\ 3x + 2y = 8

Given, two equations, Comparing these equations with , we get As we can see,  Hence, the pair of equations has exactly one solution. By Cross multiplication method,

Q1.    Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method.

                (i)    \\x - 3y -3 = 0\\ 3x - 9y -2 = 0

Given, two equations, Comparing these equations with , we get As we can see,  Hence, the pair of equations has no solution.
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