# Q&A - Ask Doubts and Get Answers

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Let the height of the tower be  m. we have PB = 4m and QB = 9 m Suppose  , so According to question, In triangle , ..............(i) In triangle , .....................(ii) multiply the equation (i) and  (ii), we get Hence the height of the tower is 6 m.
Let  be the height of the tower (DC) and the speed of the car be . Therefore, the distance (AB)covered by the car in 6 seconds is 6 m. Let  time required to reach the foot of the tower. So, BC =  According to question, In triangle , ..........................(i) In triangle , ...................(ii) Put the value of  in equation (i) we get, Hence, from point B car take 3 sec to reach the...
Let the height of the cable tower be (AB = )m Given, Height of the building is 7 m and angle of elevation of the top of the tower  , angle of depression of its foot . According to question, In triangle , since DB = CE = 7 m In triangle , Thus, the total height of the tower equal to
Given that, Height of the girl is 1.2 m. The height of the balloon from the ground is 88.2 m and the angle of elevation of the balloon from the eye of the girl at any instant is () and after some time . Let the  distance travelled by the balloon from position A to position D during the interval. AB = ED = 88.2 - 1.2 =87 m Now, In triangle , In triangle , Thus, distance travelled by the...
Given that, Height of the lighthouse (AB) is 75 m from the sea level. And the angle of depression of two different ships are  and  respectively Let the distance between both the ships be  m. According to question, In triangle , .............(i) In triangle , .............(ii) From equation (i) and (ii) we get;   Hence, the distance between the two ships is approx 55 m.
Suppose the  is the height of the tower AB and BC =  m It is given that, width of CD is 20 m,  According to question, In triangle , ............(i) In triangle ACB, .............(ii) On equating eq (i) and (ii) we get: from here we can calculate the value of    and the width of the canal is 10 m.
Given that, The height of both poles are equal  DC = AB. The angle of elevation of of the top of the poles are  and  resp. Let the height of the poles be   m and CE =  and BE = 80 -  According to question, In triangle DEC, ..............(i) In triangle AEB, ..................(ii) On equating eq (i) and eq (ii), we get  m So,  = 60 m Hence the height of both poles is ()m and the...
Let the height of the pedestal be  m. and the height of the statue is 1.6 m. the angle of elevation of the top of the statue and top of the pedestal is(  )and( ) respectively. Now,  In triangle , therefore,  BC =  m In triangle , the value of   is  m Hence the height of the pedestal is  m
It is given that, the height of the tower (AB) is 50 m.  and  Let the height of the building be  m According to question, In triangle PBQ, .......................(i) In triangle ABQ, .........................(ii) On equating the eq(i) and (ii) we get, therefore,  = 50/3 = 16.66 m = height of the building.
Suppose BC =  is the height of transmission tower and the AB be the heoght of the building and  AD is the distance between bulding and the observer point (D). We have, AB = 20 m, BC =  m and AD =  m  and  According to question, In triangle  BDA, So,  = 20 m Again, In triangle CAD, Answer- the height of the tower is 14.64 m
Given that, Height of tall boy (DC) is 1.5 m and the height of the building (AB) is 30 m.  and  According to question, In right triangle AFD, So, DF =  In right angle triangle , EF =  So, distance walked by the boy towards the building = DF - EF =
A Given that, The length of AB = 60 m and the inclination of the string with the ground at point C is . Let the length of the string AC be . According to question, In right triangle CBA, The value of length of the string ()  is  = 40(1.732) = 69.28 m Hence the length of the string is 69.28 m.
Let the height of the tower AB is  and the angle of elevation from the ground at point C is  According to question, In the right triangle , the value of  is  = 10(1.732) = 17.32 m Thus the height of the tower is 17.32 m
Suppose  m is the length of slides for children below 5 years and the length of slides for elders children be  m. Given that, AF = 1.5 m, BC = 3 m,  and  In triangle EAF, The value of  is 3 m. Similarily in CDB, the value of  is  = 2(1.732) = 3.468 Hence the length of the slide for children below 5 yrs. is 3 m and for the elder children is 3.468 m.
Suppose DB is a tree and the AD is the broken height of the tree which touches the ground at C. GIven that, , BC = 8 m  let AB =  m and AD =  m  So, AD+AB = DB =  In right angle triangle , So,  the value of  =  Similarily,  the value of  is  So, the total height of the tree is-              = 8 (1.732) = 13.856 m (approx)
Given that, The length of the rope (AC) = 20 m. and   Let the height of the pole (AB) be  So, in the right triangle  By using the Sin rule                     m. Hence the height of the pole is 10 m.
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