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G Gautam harsolia
Answer-  If  for the overall reaction is positive  feasible                                                  negativenot feasible (a)                                                                                               ---------------------------------------------------------------------------------------                                 (b)                                             ...

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G Gautam harsolia
Answer(a)- Half-reaction oxidation half    reduction half  balancing them by multiplying oxidation half by 3 and adding the reaction  

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G Gautam harsolia
In acidic medium oxidation half reaction- reduction half reaction- Balancing the reaction multiply by 2 on oxidation half-reaction then add it with reduction half reaction

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G Gautam harsolia
Answer- oxidation half reaction reduction half reaction Balancing the reaction multiply the oxidation half by 5 and reduction half by 2 and then add these two reactions   

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G Gautam harsolia
reduction half reaction   (+7 to +4)  Add 3 electron on LHS side and after that to balance charge add OH ions. And to balance O atom add water molecule on whichever side it needed balance it  oxidation half balance it  equalising the no. of electrons by multiplying the oxidation half by 3 and reduction half by 2 and then add it. final answer-  

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G Gautam harsolia
Answer- Here, by looking at the reaction, we conclude that   oxidises  and in the second reaction  not able to oxidise. So we can say that is stronger oxidizing agent than .

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G Gautam harsolia
Answer- In the first reaction, we can see that   oxidizes the phosphorus from (+1  +5) also in second, we clearly see that   oxidize the phosphorus from (+1+5). Both are oxidizing agents.

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G Gautam harsolia

 8.24 Refer to the periodic table given in your book and now answer the following questions:

 (a) Select the possible non-metals that can show disproportionation reaction.

 (b) Select three metals that can show disproportionation reaction

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G Gautam harsolia
Answers- (i)  electrode is negatively charged because it loses electrons (act as an anode) (ii) electron flow from negatively charged electrode to a positively charged electrode (anode to cathode) and the flow of current is just reversed. So current flow through silver cathode to the zinc anode. (iii) At Anode-      At Cathode 

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G Gautam harsolia
Answer- A negative electrode potential means redox couple is a stronger reducing agent. So as per data the increasing order of the following is-

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G Gautam harsolia
Answer- (iv) In aqueous solution  ionise into  and  At the cathode, the copper ion will be deposited because it has a higher reduction potential than the water molecule At the anode, the lower electrode potential value will be preferred but due to overpotential of oxygen, chloride ion gets oxidized at the anode. @ Anode-   @ cathode- 

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G Gautam harsolia
Answer- given sulphuric acid is dilute.  ionize into     At cathode  At anode, There will be -(liberation of oxygen gas)  

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G Gautam harsolia
Answer- (ii) since platinum electrode cannot easily oxidize. So at the anode    will oxidize and liberate oxygen and at cathode   will be deposited. At cathode-  At anode-  

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G Gautam harsolia
Answer-  (i)  dissociate into  and  @ Cathode -  (reduction potential of silver is higher than )  @Anode -  (oxidation potential of silver is higher than water molecule.So silver electrode oxidized )

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G Gautam harsolia
Answer- In order to displace a metal from its metal salt is done only when the other metal has higher electrode potential.

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G Gautam harsolia
Answer- we have,  number of moles(n) = given mass/ molecular mass   ------------------------------(eq.1) No. of moles of ammonia  = 10/17 = 0.588 No. of moles of oxygen  = 20/32= 0.625 Balanced Reaction    Here we see that 4 moles of ammonia required 5 moles of oxygen. So 0.588 moles of ammonia =  moles of  . But we have only 0.625 moles of . It means oxygen is a limiting reagent and the...

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G Gautam harsolia
Answer- Base equation-  --------------(have to remember) Now we have to balance the oxidation half and reduction half. oxidation half =  balancing-  Oxygen is balanced by adding water molecule, Hydrogen is balanced by  ion and for charge add (electron) Reduction hallf=  Balancing-  to balance charge add an electron    Now add both balanced oxidation half and reduction half,  we get 

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G Gautam harsolia
Answer- The base equation  write oxidation half with their oxidation state Balance the charge on  by adding 1  on RHS side. To balance charge add  ions on RHS side and then for oxygen balance add  molecule on LHS side. reduction half  balancing the reduction half by adding 1 on LHS side   Add both balanced reduction half and oxidation half
CN(aq)+CNO(aq)+H2O(l)
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G Gautam harsolia
Answer- Carbon shows different oxidation state according to the compound formula.  here we can clearly say that Carbon is in its +3 oxidation state. The oxidation state of carbon is increased(oxidized) and decreased(reduced) as well in the product side. So it is a redox reaction and more specifically we can say it disproportion redox reaction.
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