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10.   Find the sum to n terms of the series in Exercises 8 to 10 whose nth terms is given by  $( 2n-1) ^2$

nth terms is given by  .

9.   Find the sum to n terms of the series in Exercises 8 to 10 whose nth terms is given by $n^2 + 2 ^ n$

nth terms are given by  This term is a GP with first term =a =2 and common ratio =r =2.         Thus, the sum is

8.   Find the sum to n terms of the series in Exercises 8 to 10 whose nth terms is given by $n (n+1) ( n + 4 )$

nth terms is given by

7. Find the sum to n terms of each of the series in $1 ^ 2 + ( 1 ^2 +2 ^ 2 ) + ( 1 ^ 2 +2 ^ 2 + 3 ^ 2 ) ...$

series =     n th term  =

6.  Find the sum to n terms of each of the series $3 \times 8 + 6 \times 11 + 9\times 14+...$

series =             =(n th term of 3,6,9,...........)(nth terms of 8,11,14,..........)   n th term  =                                                                                                                                                                      Hence, sum is

5.   Find the sum to n terms of each of the series in $5 ^ 2 + 6 ^ 2 + 7 ^ 2 + ....+ 2 0 ^2$

series =     n th term  =                                                           16th term is                           Hence, the sum of the series   is 2840.

4.   Find the sum to n terms of each of the series in $\frac{1}{1\times 2}+\frac{1}{2\times 3}+\frac{1}{3\times 4}+ ...$

Series =                 .................................                                                                                      Hence, the sum is

3.   Find the sum to n terms of each of the series  $3 \times 1 ^ 2 + 5 \times 2 ^ 2 + 7 \times +....+ 20 ^ 2$

the series   nth term  =                                                                                                                                                    Thus, the sum is

2.   Find the sum to n terms of each of the series in  $1 \times 2 \times 3 + 2 \times 3 \times 4 + 3 \times 4 \times 5 + ...$

the series =   n th term  =                                                                                                                                                                                                              Thus, sum is

1.   Find the sum to n terms of each of the series in $1 \times 2 + 2 \times 3 + 3 \times 4 + 4 \times 5 + ...$

the series =  n th term  =
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