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S seema garhwal
n(french) = 50 n(spanish) = 20 n(speak both french and spanish) = 10 n(speak at least one of these two languages) = n(french) + n(spanish) - n(speak both french and spanish) n(speak at least one of these two languages) = 50  + 20 - 10 n(speak at least one of these two languages) = 70 -10 n(speak at least one of these two languages) = 60 Hence,60 people speak at least one of these two languages.

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S seema garhwal
Total people = 65 n(like  cricket) = 40 n(like both cricket and tennis) = 10 n(like tennis) = ? Total people = n(like  cricket)   +   n(like tennis)  -  n(like both cricket and tennis)  n(like tennis) = 65 - 40 + 10  n(like tennis) = 35 Hence,35 people like tennis. n (people like only tennis) =  n(like tennis) - n(like both cricket and tennis) n (people like only tennis) = 35 - 10 n (people...

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S seema garhwal
n(people like coffee) = 37  n(people like tea ) = 52 Total number of people = 70  Total number of people = n(people like coffee)  +   n(people like tea )  - n(people like both tea and coffee)                              70  =  37  +   52 - n(people like both tea and coffee) n(people like both tea and coffee)  =  89 - 70  n(people like both tea and coffee)  =  19  Hence,19 people like both...

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S seema garhwal
n( X  Y) = 60 n( X ∩ Y) = 10 n(X) = 40 n( X  Y) =  n(X)  +  n(Y)   -  n( X ∩ Y)        n(Y) = 60 - 40 + 10        n(Y) = 30 Hence,set Y has 30 elements.

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S seema garhwal
n(S) = 21 n(T) = 32 n(S   T) = 11 n(S  T) = n(S) + n(T) - n(S   T)  n(S T) = 21 +  32 - 11 n(S T) = 53 - 11 n(S  T)  = 42 Hence, the set  (S  T)  has 42 elements.    

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S seema garhwal
Hindi speaking = 250 = n(A) English speakind = 200 = n(B) Group of people = 400 = n(A  B) People speaking both Hindi and English = n(A  B) n(A  B) = n(A) + n(B) - n(A  B) n(A  B) = 250 + 200 - 400 n(A  B) = 450 - 400 n(A  B)  = 50 Thus,50 people speak hindi and english both.  

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S seema garhwal
n( X  Y ) = 18 n(X) = 8 n(Y) = 15 n( X  Y ) =  n(X) + n(Y) - n(X  Y) n(X  Y) = 8 + 15 - 18  n(X  Y) = 5  

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S seema garhwal
n( X ) = 17,       n( Y ) = 23             and  n( X  Y ) = 38 n( X  Y ) = n( X ) + n( Y ) - n ( X  Y )          38  =  17 + 23 - n ( X Y )  n ( X Y ) =  40 - 38 n ( X Y ) = 2.
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