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G Gautam harsolia
Points are collinear means they lies on same line Now,  given points are    and   Equation of line passing through point A and B is Therefore, the equation of line passing through A and B is  Now, Equation of line passing through point B and C is Therefore, Equation of line passing through point B and C is  When can clearly see that  Equation of line passing through point A nd B ...

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G Gautam harsolia
Let the coordinates of Point A is (x,0) and of point B is (0,y) It is given that point R(h , k) divides the line segment between the axes in the ratio  Therefore, R(h , k)  Therefore, coordinates of point A is   and of point B is  Now, slope of line passing through points  and   is  Now, equation of line passing through point   and with slope  is  Therefore, the equation of line is 

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G Gautam harsolia
Now, let coordinates of point A is (0 , y) and of point B is (x , 0) The, Therefore, the coordinates of point A is (0 , 2b) and of point B is (2a , 0) Now, slope of line passing through points (0,2b) and (2a,0) is Now, equation of line passing through point (2a,0) and with slope    is Hence proved

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G Gautam harsolia
It is given that the owner of a milk store sell 980 litres milk each week at  and    litres of milk each week at   Now, if we assume the rate of milk as x-axis and Litres of milk as y-axis Then, we will get coordinates of two points i.e.  (14, 980)  and   (16, 1220) Now, the relation between  litres of milk and Rs/litres is given by equation  Now, at  he could sell He could sell...

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G Gautam harsolia
It is given that If  then  and  If    then   Now, if assume C along x-axis and L along y-axis Then, we will get coordinates of two points (20 , 124.942)  and (110 , 125.134) Now, the relation between C and L is given by equation Which is the required relation

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G Gautam harsolia
Let the slope of the line is m and slope of a perpendicular line is which passes through the origin (0, 0) and (-2, 9) is Now, the slope of the line is Now, the equation of line passes through the point (-2, 9) and with slope   is Therefore, the equation of the line is     

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G Gautam harsolia
We know that  Now, equation of line passing through point (0 , 2) and with slope  is Therefore, equation of line is                   -(i) Now, It is given that line crossing the -axis at a distance of units below the origin which means coordinates are  (0 ,-2) This line is parallel to above line which means slope of both the lines are equal Now, equation of line passing through point...

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G Gautam harsolia
Let (a, b) are the intercept on x and y axis respectively Then, the equation of line is given by It is given that a + b = 9  b = 9 - a Now, It is given that line passes through point (2 ,2) So, case (i)  a = 6  b = 3   case (ii)   a = 3 , b = 6 Therefore, equation of line is 2x + y = 6 , x + 2y = 6

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G Gautam harsolia
Let (a, b) are the intercept on x and y-axis respectively Then, the equation of the line is given by Intercepts are equal which means a = b Now, it is given that line passes through the point (2,3) Therefore, therefore, equation of the line is     

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G Gautam harsolia
Co-ordinates of point which divide line segment joining the points    and    in the ratio  is Let the slope of the perpendicular line is m And Slope of  line segment joining the points    and   is Now, slope of perpendicular line is Now, equation of line passing through point  and with slope m is equation of line passing through point  and with slope  is Therefore, equation of line  is  

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G Gautam harsolia
It is given that the line passing through    and perpendicular to the line through the points    and Let the slope of the line passing through the point (-3,5) is m and Slope of line  passing through points (2,5) and (-3,6) Now this line is perpendicular to line passing through point (-3,5) Therefore, Now, equation of line passing through point  and with slope m is equation of line...

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G Gautam harsolia
 The vertices of   are    and    Let m be RM b the median through vertex R Coordinates of M (x, y ) =  Now, slope of line RM Now, equation of line passing through point  and with slope m is equation of line passing through point (0 , 2) and with slope  is Therefore, equation of median is 

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G Gautam harsolia
 It is given that length of perpendicular is 5 units  and  angle made by the  perpendicular with the positive -axis is   Therefore, equation of line is In this case p = 5 and   Therefore, equation of the line  is   

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G Gautam harsolia
We know that , equation of line passing through point  and with slope m is given by Now, it is given that line passes throught point (-1 ,1) and (2 , -4) Now,  equation of line passing through point (-1,1) and with slope   is   

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G Gautam harsolia
We know that , equation of line passing through point  and with slope m is given by Line Intersecting the y-axis at a distance of 2 units above the origin which means point is (0,2) we know that Now, the equation of the line passing through the point (0,2) and with slope   is  Therefore, the equation of the line  is   

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G Gautam harsolia
We know that the equation of the line passing through the point  and with slope m is given by Line Intersecting the -axis at a distance of  units to the left of origin which means the point is (-3,0) Now, the equation of the line passing through the point (-3,0) and with slope -2  is  Therefore, the equation of the line  is   

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G Gautam harsolia
We know that the equation of the line passing through the point  and with slope m is given by we know that where  is angle made by line with positive x-axis measure in the anti-clockwise direction Now, the equation of the line passing through the point  and with slope   is  Therefore, the equation of the line  is   

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G Gautam harsolia
We know that the equation of the line passing through the point  and with slope m is given by Now, the equation of the line passing through the point (0,0) and with slope m is  Therefore, the equation of the line  is   

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G Gautam harsolia
We know that , equation of line passing through point  and with slope m is given by Now,  equation of line passing through point (-4,3) and with slope  is  Therefore, equation of the line  is   
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