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4.2     For the reaction:
           2A+B\rightarrow A_{2}B
           the rate =k\left [ A \right ]\left [ B \right ]^{2} with k=2.0\times 10^{-6}mol^{-2}L^{2}s^{-1}. Calculate the initial rate of the reaction when\left [ A \right ]=0.1 mol L^{-1}\: \: ,\left [ B \right ]=0.2 mol L^{-1}. Calculate the rate of reaction after \left [ A \right ] is reduced to 0.06molL ^{-1}.

The initial rate of reaction =   substitute the given values of [A], [B] and k, rate  =          =8 When [A] is reduced from 0.1 mol/L to 0.06 mol/L  So, conc. of A reacted = 0.1-0.06 = 0.04 mol/L and conc. of B reacted = 1/2(0.04) = 0.02mol/L conc. of B left = (0.2-0.02) = 0.18 mol/L     Now,  the rate of the reaction is (R) =                                                                  ...
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