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  Aniline on bromination in the presence of water gives 2,4,6 tribromoaniline, which on further reacting with nitrous acid converts  into . Now, with the help of  it removes the  group from the benzene ring and we get our final product 1,3,5 tribromobenzene.
    On diazotisation, reaction  will convert to . And then reacts with fluoroboric acid followed by  convert  into the nitro group     () and evolution of dinitrogen gas.
structures of different isomers corresponding to the molecular formula  and their IUPAC name- (i) Propan-1-amine   (ii) Propan-2-amine   (iii) N – Methylethanamine (iv) N, N-Dimethylmethanamine   The structure (i) and (ii) will liberate nitrogen gas () on treating with nitrous acid.  
When aniline reacts with benzoyl chloride HCl is produced as a by-product and N-phenyl benzamide is produced as a major product. lone pair of N atom attacks the acidic carbon of benzoyl chloride.  
The methyl iodide reacts with aniline to give  N, N-dimethylaniline.   With the excess of methyl iodide in the presence of sodium carbonate solution (), N, N-dimethylaniline produces N, N, N-trimethyl anilinium carbonate.    
On considering the inductive effect, solvation effect and steric hindrance of the alkyl group which decides the basic strength of alkyl amines in the aqueous state. The order of basic strength in case of methyl substituted amines are - 
On considering the inductive effect, solvation effect and steric hindrance of the alkyl group the increasing order of basicity in ethyl as a substituted group is shown above.
Considering the inductive effect, solvation effect and steric hindrance of the alkyl group which decides the basic strength of alkylamines. order of basic strength in ethyl substituted amine is- and order in benzene substituted ring- Due to the -R effect of benzene  has less electron density than ammonia. So, the final order is -
  ON reacting the given reactant with ethanolic sodium cyanide, the CN molecules replace both chlorine atom. And after that catalytic hydrogenation, we get our desired product. (reduce the CN to in both sides)
  Nitration of benzene gives nitrobenzene and after catalytic hydrogenation of nitrobenzene, it gives aniline. Aniline on reacting with two moles of chloromethane to form N, N-dimethylaniline.
  Nitration of benzene gives nitrobenzene. And now reduce the nitro group by catalytic hydrogenation.
  Butanamine (Chain isomerism + position isomerism) Butan-2-amine (chain isomerism + position isomerism) 2-Methylpropanamine (chain isomerism) N-Methylpropan-2-amine (position isomerism + metamerism) 2-Methylpropan-2-amine (chain isomerism) N,N-Dimethylethanamine N-Methylpropanamine (position...
IUPAC name of all the isomers- Butanamine Butan-2-amine 2-Methylpropanamine N-Methylpropan-2-amine 2-Methylpropan-2-amine N,N-Dimethylethanamine N-Methylpropanamine N-Ethylethanamine
different isomeric amines corresponding to the molecular formula,  (i )                                         (v)   (ii)                                          (vi)   (iii)                                            (vii)          (iv)                                                    (viii)                             
In structure, we can clearly see that N is directly connected with 2 carbon atom. so, it is a secondary amine.
Here N atom directly connected with only one C atom. So it is a primary aliphatic amine.
In this compound N atom directly connected with 3 carbon atoms. So, it is a tertiary aromatic amine
N atom is directly connected with only one C atom, so it is a primary aromatic amine  
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