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(vii) The mechanism of the given reaction reaction is :-                       
(vi) The mechanism for the reaction is given below :-                              
The structures of  o-Dichlorobenzene,  m-Dichlorobenzene and  p-Dichlorobenzene are given below.                                                                     We can see that p-Dichlorobenzene is a very symmetric structure thus packing of it will be maximum. As a result more and more energy will be required to break bonds (during boiling). Thus boiling point is high...
Hydrolysis by KOH will take place by the formation of a carbocation in its rate-determining step. So the compound having stable carbocation will hydrolyse faster. The carbocations of both the compounds are given below:-              It is clear that carbocation of  is more stable.  Hence   will hydrolyse faster than .
(iii)  The steric hindrance is the deciding factor here. The order of steric hindrance is :-      1-Bromobutane < 1-Bromo-3-methylbutane < 1-Bromo-2-methylbutane< 1-Bromo-2, 2-dimethylpropane Thus the order of the rate of reaction will be : -  1-Bromo-2, 2-dimethylpropane < 1-Bromo-2-methylbutane < 1-Bromo-3- methylbutane < 1-Bromobutane
(ii) In this case, also, the order of the rate of reaction will be decided from the steric hindrance factor.                   It is clear from the above that the steric hindrance in 2-Bromo-2-methylbutane highest (note that hindrance of the carbon attached to halide ion is seen). So the order of the rate of reaction is:-                       2-Bromo-2-methylbutane < 2-Bromo-3-methylbutane <...
(i)  Here the deciding factor the rate of reaction will be a steric hindrance.                      It is clear from the above that the order of hindrance is:-    1-Bromopentane < 2-bromopentane < 2-Bromo-2-methylbutane So the order of rate of reaction will be:-          2-Bromo-2-methylbutane < 2-Bromopentane < 1-Bromopentane
The reaction will proceed through SN2 mechanism. The mechanism for the given reaction is shown below :-