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D Devendra Khairwa
Dissociation of K2SO4 is as follows :-                                     It is clear that 3 ions are produced, so the value of i will be 3. Molecular weight of K2SO4 = 2(39) + 1(32) + 4(16) = 174u.                                                  Putting all the values :-                                                                                    

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D Devendra Khairwa
We know that osmotic pressure :                                                      or                                                  We have been given the values of osmotic pressure, V, i and T. So the value of w can be found.                                                                                                                                                                  ...

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D Devendra Khairwa
We have been given that the water is in equilibrium with air at a pressure of 10 atm or 7600 mm of Hg.  So the partial pressure of oxygen :                                                              and partial pressure of nitrogen :                                                              Now, by Henry's Law :                                       For oxygen :                           ...

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D Devendra Khairwa
Firstly, we will find the no. of moles of the given compounds. No. of moles of benzene :                                                  and the no. of moles of toluene :                                                  . Now we will find mol fraction of both:-  Mole fraction of benzene :-                                                       and mole fraction of toluene :                     ...

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D Devendra Khairwa
For calculating partial vapour pressure we need to calculate mole fractions of components. So number of moles of liquid A :                                                          and  moles of liquid B :                                                         Mole fraction of A (xA)   :                                                        and mole fraction of B (xB)  :                     ...

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D Devendra Khairwa
We know that :             We are given value of P and k, so C can be found.                                       Hence solubility of methane in benzene is .

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D Devendra Khairwa
Firstly we will find number of moles of both water and glucose. Moles of glucose :                                                                           and moles of water :                                                                                 Now,                                               or                                        or                                       ...

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D Devendra Khairwa
Firstly we need to calculate molality in order to get vant's hoff factor. So moles of CH2FCOOH :                                                  We need to assume volume of solution to be nearly equal to 500 mL.         (as 500 g water is present) Now, we know that :             or                                            Now for dissociation constant :-                                     ...

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D Devendra Khairwa
Firstly we will find the Vant's Hoff factor the dissociation of given compound.                  So we can write,                                              or                                                                                                                        or                                                                       Putting values of Ka and C in the last...

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D Devendra Khairwa
We know that depression in freezing point of water will depend upon the degree of ionisation. The degree of ionisation will be highest in the case of trifluoroacetic acid as it is most acidic among all three. The order of degree of ionisation on the basis if acidic nature will be:-     Trifluoroacetic acid > Trichloroacetic acid > Acetic acid. So the depression in freezing point will be reverse...

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D Devendra Khairwa
Molar mass of benzoic acid = 7(12) + 6(1) + 2(16) = 122u. We are given with the molarity of solution.                                                    or                                                           or                                       So mass of benzoic acid :                                                                                               Hence the required...

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D Devendra Khairwa
We are given with molality of the solution, so we need to find the moles of Nalorphene. Molar mass of nalorphene =  19(12) + 21(1)  + 1(14) + 3(16)  =  311u. So moles of nalorphene :                                               Molality :                                                            or                                                        or                                     ...

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D Devendra Khairwa
Total mass of solution = Mass of aspirin + Mass of acetonitrile = 6.5 + 450 = 456.5 g. We know that :                             So,                                                  Thus the mass percentage of aspirin is

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D Devendra Khairwa
We are given,       The dissociation equation of CuS is given by :-                                         So, the equation becomes :-    or                                             or                                                      Thus maximum molarity of solution is   .

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D Devendra Khairwa
We know that, Molality :                                            So, for moles of solute we have :                                Thus,  molality :                                          Molality of Na+ ions is 4m.

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D Devendra Khairwa
Ethylene glycol is an organic compound but is polar in nature. Also, it can form H-bonds with water molecules, thus it is highly soluble in water.

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D Devendra Khairwa
Since the -OH group in formic acid (polar) can form H-bonds with water thus it is highly soluble in water.
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