The inductance of the inductor
The capacitance of the capacitor
Voltage supply
Frequency of voltage supply .
Here, we have
Impedance
Now,
Current in the circuit will be
where,
The negative sign is just a matter of the direction of current.so,
here
But, since the value of R is zero(since our circuit have only L and C)
Hence
Now,
RMS value of this current:
.

As we know, in the case of a parallel RLC circuit:
The current will be minimum when
Which is also the condition of natural frequency. Hence the total current is minimum when source frequency is equal to the natural frequency.
RMS value of current in R
RMS value in Inductor
RMS value in capacitor
Capacitor current and inductor current will cancel out each other so the current flowing in...

Given,
The capacitance of the capacitor
The resistance of the circuit
Voltage supply
Frequency of voltage supply
The maximum current in the circuit
Hence maximum current in the circuit is 3.9A.
b)
In the case of capacitor, we have
So,
So the time lag between max voltage and max current is :
At high frequencies, tends to zero. which indicates capacitor acts as a conductor at high...

In the case of a capacitor, we have
So,
So the time lag between max voltage and the max current is :

Given,
The capacitance of the capacitor
The resistance of the circuit
Voltage supply
Frequency of voltage supply
The maximum current in the circuit
Hence maximum current in the circuit is 3.24A.

Given,
The inductance of the coil
the resistance of the coil
Supply voltage
Supply voltage frequency
a)
Now, as we know peak voltage = (RMS Voltage)
Peak voltage
Now,
The impedance of the circuit :
Now peak current in the circuit :
Hence peak current is in the circuit.
The current in the circuit is very small, which is one of the indications of inductor working as a nearly open circuit...

Let the voltage in the circuit be
and
Current in the circuit be
Where is the phase difference between voltage and current.
V is maximum At
t = 0
is maximum At
Hence, the time lag between voltage maximum and the current maximum is
.
For phase difference we have
Hence time lag between the maximum voltage and the maximum current is

Given,
The inductance of the coil
the resistance of the coil
Supply voltage
Supply voltage frequency
Now, as we know peak voltage = (RMS Voltage)
Peak voltage
The impedance of the circuit :
Now peak current in the circuit :
Hence peak current is 1.82A in the circuit.

If the resistance is added to the circuit, the whole energy will dissipate as heat eventually. energy will keep moving between the capacitor and inductor with reducing in magnitude in each cycle and eventually all energy will be dissipated.

The energy will be shared equally when the energy in the capacitor is half of the maximum energy it can store.i.e.
From Here, we got
So Now, we know the charge on the capacitor, we can calculate time for which
From here,
Hence for these times, the total energy will be shared equally between capacitor and inductor.

The stored energy will we purely magnetic when the pure electrical stored is zero. i.e. when the charge on the capacitor is zero, all energy will be stored in the inductor.
So, t for which charge on the capacitor is zero is
Hence at these times, the total energy will be purely magnetic.

at any instant, the charge on the capacitor is:
Where time period :
Now, when the total energy is purely electrical, we can say that
this is possible when
Hence Total energy will be purely electrical(stored in a capacitor) at
.

Given,
The inductance of the inductor:
The capacitance of the capacitor :
The initial charge on the capacitor:
The natural angular frequency of the circuit:
Hence the natural angular frequency of the circuit is .
The natural frequency of the circuit:
Hence natural frequency of the circuit is 159Hz.

Given,
The inductance of the inductor:
The capacitance of the capacitor :
The initial charge on the capacitor:
Total energy present at the initial moment:
Hence initial energy in the circuit is 1J. Since we don't have any power-consuming element like resistance in the circuit, the energy will be conserved

Potential difference across any element =
NOW,
The potential difference across capacitor:
Potential difference across the inductor
The potential difference across Resistor
Potential difference across LC combination
Hence at resonating frequency potential difference across LC combination is zero.

Given,
Variable frequency supply voltage = 230V
Inductance
Capacitance
Resistance
Now,
The impedance of the circuit is
at Resonance Condition
:
Hence, Impedance at resonance is 40.
Now, at resonance condition, impedance is minimum which means current is maximum which will happen when we have a peak voltage, so
Current in the Resonance circuit is Given by
Hence amplitude of the current...

Given,
Variable frequency supply voltage = 230V
Inductance
Capacitance
Resistance
a) Resonance angular frequency in this circuit is given by :
Hence this circuit will be in resonance when supply frequency is 50 rad/sec.

Given,
Range of the frequency in which radio can be tune =
The effective inductance of the Circuit =
Now, As we know,
where is tuning frequency.
For getting the range of the value of a capacitor, let's calculate the two values of the capacitor, one maximum, and one minimum.
first, let's calculate the minimum value of capacitance which is the case when tuning frequency = 800KHz.
Hence...

Given,
Resistance
Inductance
Capacitance
Voltage supply
At resonance, supply frequency is equal to the natural frequency, and at the natural frequency, the total impedance of the circuit is equal to the resistance of the circuit
as inductive and capacitive reactance cancels each other. in other words,
As
Now,
Current in the circuit
Average Power transferred in the circuit :
Hence...

Given
Capacitance
Inductance
Charge on the capacitor
Now,
The total energy stored in Capacitor :
Total energy later will be same because energy is being shared with capacitor and inductor and none of them loses the energy, they just store it and transfer it.

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