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Given that, Length of each slab =  So, the length of the square =  (a) The first figure is a square So, the perimeter of the square = 4  side                                                    =  (b) The perimeter of the 2nd figure = Sum of all the sides =  = 10 m (c) Figure (ii) has a greater perimeter than fig (i) (d) Arrange all the slab in horizontally, it forms a rectangle whose...
(a) The perimeter of the square       = Sum of all the four side = 4   side       = 4   25       = 100 cm (b)The perimeter of the rectangle = SUm of all the sides = 2  [length + breadth ) = 2  (20 + 30) = 2  50 = 100 (c)The perimeter of the rectangle = Sum of all the sides = 2  [length + breadth ] = 2  (40 + 10) = 2  50 = 100 cm (d)The perimeter of the triangle = Sum of all three...
Given that, Length of the square park = 75m Length and breadth of the rectangular park is 60 m and 45m respectively Therefore, The perimeter of the square park  = 4  75  =300 m Also, the Perimeter of the rectangular park = 2 ( 60 + 45) =2 105m =210m Hence Bulbul covers the less distance.
Given that, The length of the rectangular park is 15 m and the breadth is 125m. Cost of fencing rate = Rs 12 per meter Therefore, Perimeter of the park =2 [L + B] = 2 [175 +125] =2  300m =600m So, the total cost of fencing = 600   12  = Rs. 7,200
Given that, Length of the square park  = 250 m Cost of fencing = rs. 20 per meter Therefore, the Perimeter of the square park = = 4  250 =1000 m = 1km So, total cost = 20   1000 = 20,000 Rs
Given that, The two sides of the triangle are 12 cm and 14 cm. let the third side be A. And the perimeter of the triangle is 36cm. Therefore, the Perimeter of the triangle   = sum of all sides of the triangle   = 12cm +14cm + A = 36cm   = A + 26cm =36cm   = A = 10cm   
Given that, Length of the string is 30 cm (a)For square, Number of sides = 4 Therefore, Length of one side = 30 /4 = 7.5 cm (b)For equilateral triangle, Number of sides = 3 Therefore, length of sides = 30/3 = 10cm (c) For a regular hexagon, Number of sides = 6 Therefore, Length of one side = 30/6 = 5cm  
Given, The perimeter of a regular pentagon is 100cm and, no. of sides in regular pentagon is five (5) therefore, the length of each side 
Given that, The perimeter of the square is 20m According to question, The perimeter of square = 4  side  
It is known that, A regular hexagon has six equal sides. So, the perimeter of the regular hexagon   = 6  side   = 6  8m = 48m
We all know that,  Perimeter of a triangle = sum of all the sides of the triangle                              =10cm + 14cm +15cm                              = 39 cm               
   (a) The perimeter of a triangle = Sum of all the three sides                                                     = 3cm + 4cm + 5cm                                                      = 12 cm  (b) The perimeter of a eqilateral triangle       = Sum of all the sides of  the triangle        = (9cm +9cm +9cm)        = 27cm (c) Perimeter of a given isosceles triangle       = Sum of all...
We have,   A rectangular piece of land measures 0.7 km by 0.5 km and side is to be fenced with 4 rows of wires. As per the question, Required length of wires = 4 2 [ 0.7 km + 0.5 km] = 8  1.2 km = 9.6 km
We have, Length and breadth of a photograph is 32 cm and 21 cm respectively. So, According to question, Length of wooden strip required to frame the photograph = 2 [L + B]                                                                                             = 2 [32 + 21] cm                                                                                             = 2   53 cm  = 106...
We have table-top measures 2 m 25 cm by 1 m 50 cm. Therefore, the Perimeter of the table-top = sum of all sides                                                                   = 2(L+B)                                                                  = 2 ((2m + 0.25m) + (1m + 0.5m))                                                                  = 7.5 m  
We have, Length = 40 cm and, Breadth = 10 cm So, the length of tape required = perimeter of the rectangular box                                                   = 2 (L + B)                                                   = 2 50 cm                                                   = 100 cm Hence 100 cm tape is required.
The perimeter of the following figures- Perimeter = sum of all sides  Therefore,  (a) Perimeter = 4 cm + 2cm +1 cm +5cm = 12 cm (b) Perimeter = 23 cm + 35 cm + 40cm + 35cm = 133 cm (c) Required perimeter = 15cm + 15 cm + 15 cm +15 cm = 60 cm (d) Required perimeter= (4 + 4 + 4 + 4 + 4) cm = 20 cm (e) Perimeter = 4cm + 0.5 cm +2.5cm +2.5cm + 0.5cm +4cm +1cm = 15cm (f) Perimeter = Sum of all...
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