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A Amit Singh
Sum of all probabilities = Ptotal  =P(Family, chosen at random has 2 girls) +P(Family, chosen at random has 1 girl) + P(Family, chosen at random has no girl) = 475/1500 + 814/1500 + 211/1500 = 1500/1500 =1 Must be the result we must get. 

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A Amit Singh
The below-written data is representing the blood groups of 30 students study in class VIII. A, B, O, O, B, A, O, O, AB, O, A, O, B, A, O A, AB, O, A, A, B, A, B, O, O, O, AB, B, A, O Total no. of students = 30  Total no. of students of this class who has blood group AB =3 P(Student of this class has blood group AB)= 3/30 => 1/10 Ans: 1/10

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A Amit Singh
The data is representing the concentration of sulfur dioxide in the air in parts per million (ppm) of a city. The data obtained for a month of 30 days is as follows: Total no. of days =30 No. of days in which Conc. of sulfur dioxide in the interval 0.12 - 0.16 = 2 P(Conc. of sulphur dioxide in the interval 0.12 - 0.16) =2/30 Ans: 1/15

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A Amit Singh
From the above question, the data of our interest is: Total no. of bags = 11 Total no. of bags that contain more than 5 kg flour = 7 P(Bag contain more than 5 kg flour) = 7/11 Ans: 7/11 

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A Amit Singh
This activity can be taken as a general problem:  Well, we know the divisibility by 3 is when the sum of all the digits is divisible by 3 So, The student will write the number between 100-999 There are 900 3-digit numbers, which are 100, 101, 102, 103, ..., 999. The first 3-digit numbers that are exactly divisible by 3 is 102, 105, ..... 999 total numbers which are divisible by 3 = 300 P(the...

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A Amit Singh
This activity can be taken as a general problem: Assumption: Let the frequency of two-wheelers = x Let the frequency of three-wheelers = y Let the frequency of  four-wheelers = z Total no. of vehicles= x+y+z therefore, P(anyone vehicle out of the total vehicles I have observed is a two-wheeler) =     

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A Amit Singh
  Hey, don't you think its too simple: Well, there is no such engineer whose distance between residence and place of work is less than 1/2 km Therefore, engineer whose distance between residence and place of work is less than 1/2 km =0  P(engineer whose distance between residence and place of work is less than 1/2 km) = 0 Ans: 0

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A Amit Singh
  Total no. of engineers = 40 Total no. of engineers who are living less than 7 km from their workplace = 31 Therefore we can say, P(engineers who are living more than or equal to 7 km from their workplace)=31/40 Ans:  31/40

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A Amit Singh
Total no. of engineers = 40 Total no. of engineers who are living less than 7 km from their workplace = 9  Therefore we can say, P(engineers who are living less than 7 km from their workplace)=  = 9/40 Ans: 9/40                  

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A Amit Singh
From the above question, the data of our interest is: Total no. of students =135+65=200 Total no. of students who do not like it.= 65 P(a student does not like it) = 65/200 = 13/40  Ans: 13/40   

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A Amit Singh
From the above question, the data of our interest is: Total no. of students =135+65 =200 Total no. of students who like statistics = 135 P(students like statistics )= 135/200 =27/40  Ans: 27/40   

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A Amit Singh
From the above question, the data of our interest is: Total no. of students =90  Total no. of students who obtained marks 60 or above = 15+8 =23 P(a student obtains marks 60 or above) = 23/90  Ans: 23/90 

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D Divya Prakash Singh
From the above question, the data of our interest is: Total no. of students =90  Total no. of students who obtained marks 60 or above = 15+8 =23 P(a student obtains marks 60 or above) = 23/90  Ans: 23/90 

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A Amit Singh
From the above question, the data of our interest is: Total no. of students =90  Total no. of students who obtained less than 20% in the mathematics test= 7 P(student obtained less than 20% in the mathematics test) = 7/90  Ans: 7/90     

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A Amit Singh
Although it is given that, Total no. of families= 2400 Let us find by this adding all the cases = 10+0+1+2+1+160+305+535+469+579+25+27+29+59+82+0+2+1+25+88 =2400  Total number of families owning not more than 1 vehicle= 10+0+1+2+1+160+305+535+469+579 = 2062 Let, P(families owning not more than 1 vehicle)= P5 P5 = 2062/2400

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A Amit Singh
Although it is given that, Total no. of families= 2400 Let us find by this adding all the cases = 10+0+1+2+1+160+305+535+469+579+25+27+29+59+82+0+2+1+25+88 =2400  Total number of families,those are earning Rs.13000 – 16000 per month and owning more than 2 vehicles = 25 P(earning Rs.13000 – 16000 per month and owning more than 2 vehicles)= P4 P4 = 25/2400 =1/96 Ans:1/96

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A Amit Singh
Although it is given that, Total no. of families= 2400 Let us find by this adding all the cases = 10+0+1+2+1+160+305+535+469+579+25+27+29+59+82+0+2+1+25+88 =2400  Total no. of families, those are earning less than Rs. 7000 per month and not having any vehicle = 10 P(earning less than Rs. 7000 per month and does not have any vehicle)= P3 P3 = 10/2400 =1/240 Ans: 1/240

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A Amit Singh
Although it is given that, Total no. of families= 2400 Let us find by this adding all the cases = 10+0+1+2+1+160+305+535+469+579+25+27+29+59+82+0+2+1+25+88 =2400  Total no. of families earning Rs.16000 or more per month and owning exactly 1 vehicle = 579 P(earning Rs.16000 or more per month and owning exactly 1 vehicle )= P2 P2 = 579/2400
Although it is given that, Total no. of families= 2400 Let us find this by adding all the cases = 10+0+1+2+1+160+305+535+469+579+25+27+29+59+82+0+2+1+25+88 =2400  Earning Rs. 10000 – Rs.13000 per month and owning exactly 2 vehicles =29 P(Earning Rs. 10000–Rs.13000 per month and owning exactly 2 vehicles)= P1 P1 = 29/2400  

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A Amit Singh
Total no. of students = 40  Total no. of students who all are born in August  =6 P( a student of the class was born in August) =6/40 =3/20 Ans: 3/20      
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