Given, a cylinder with a base.
The radius of the cylinder =
Height of the cylinder =
We know,
The lateral surface area of a cylinder of radius and height =
Area of the cylindrical penholder = Lateral areal + Base area
Area of 35 penholders =
Therefore, the area of carboard required is
Given, a cylindrical lampshade
Daimeter of the base =
Height of the cylinder =
Total height of lampshade=
We know,
Curved surface area of a cylinder of radius and height =
Now, Cloth required for covering the lampshade = Curved surface area of the cylinder
Therefore, cloth will be required for covering the lampshade.
Given, a closed cylindrical petrol tank.
The diameter of the tank =
Height of the tank =
Now, Total surface area of the tank =
Now, let of steel sheet be actually used in making the tank
Since of steel was wasted, the left of the total steel sheet was used to made the tank.
The total surface area of the tank =
Therefore, of steel was actually used in making the tank.
Given, a closed cylindrical petrol tank.
The diameter of the tank =
Height of the tank =
We know,
The lateral surface area of a cylinder of radius and height =
The lateral surface area of a cylindrical tank =
Therefore, the lateral or curved surface area of a closed cylindrical petrol storage tank is
Given,
Length of the cylindrical pipe =
Diameter =
The total radiating surface will be the curved surface of this pipe.
We know,
The curved surface area of a cylindrical pipe of radius and length =
CSA of this pipe =
Therefore, the total radiating surface of the system is
Given,
Inner diameter of the circular well =
Depth of the well =
The inner curved surface area of the circular well is
Now, the cost of plastering the curved surface per = Rs. 40
Cost of plastering the curved surface of =
Therefore, the cost of plastering the well is
Given,
The inner diameter of the circular well =
Depth of the well =
We know,
The curved surface area of a cylinder =
The curved surface area of the well =
Therefore, the inner curved surface area of the circular well is
Given, a right circular cylinder
Curved surface area of the cylinder =
Radius of the base =
Let the height of the cylinder be
We know,
Curved surface area of a cylinder of radius and height =
Therefore, the required height of the cylinder is
Given,
Radius of the cylindrical pillar, r =
Height of the cylinder, h =
We know,
Curved surface area of a cylinder =
Curved surface area of the pillar =
Now,
Cost of painting of the pillar =
Cost of painting the curved surface area of the pillar =
Therefore, the cost of painting curved surface area of the pillar is
Given,
The diameter of the cylindrical roller =
Length of the cylindrical roller =
The curved surface area of the roller =
Area of the playground =
Therefore, the required area of the playground =
Note: There are two surfaces, inner and outer.
Given,
Height of the cylinder,
Outer diameter =
Inner diameter =
Outer curved surface area =
Inner curved surface area =
Area of the circular rings on top and bottom =
The total surface area of the pipe =
Therefore, the total surface area of the cylindrical pipe is
Note: There are two surfaces, inner and outer.
Given,
Height of the cylinder,
Outer diameter =
Inner diameter =
Outer curved surface area =
Therefore, the outer curved surface area of the cylindrical pipe is
Note: There are two surfaces, inner and outer.
Given,
Height of the cylinder,
Outer diameter =
Inner diameter =
Inner curved surface area =
Therefore, the inner curved surface area of the cylindrical pipe is
Given,
Height of the cylindrical tank =
Base diameter =
We know,
The total surface area of a cylindrical tank =
Therefore, square metres of the sheet is
Given,
The curved surface area of the cylinder =
And, the height of the cylinder,
We know, Curved surface area of a right circular cylinder =
Therefore, the diameter of the cylinder =