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H Harsh Kankaria
Given, Height =  The radius of the cylindrical bowl  =   The volume of soup in a bowl for a single person =   The volume of soup given for 250 patients = Therefore, the amount of soup the hospital has to prepare daily to serve 250 patients is

H Harsh Kankaria
Given, Length of the cylindrical pencil =  The radius of the graphite (Inner solid cylinder)  =  Radius of the pencil (Inner solid graphite cylinder + Hollow wooden cylinder) = =  We know, Volume of a cylinder=   The volume of graphite =  And, Volume of wood =  Therefore, the volume of wood is  and the volume of graphite is

H Harsh Kankaria
(Using capacity(volume), we will find the radius and then find the surface area) The capacity of the vessel = Volume of the vessel = litres Height of the cylindrical vessel =  Let the radius of the circular base be   The volume of the cylindrical vessel =  Therefore, the total surface area of the vessel =  Therefore, square metres of metal sheet needed to make it is

H Harsh Kankaria
(iii) Height of the cylinder =  Radius of the base of the vessel =    Volume of the cylindrical vessel =  Therefore, the capacity of the cylindrical vessel is

H Harsh Kankaria
The inner curved surface area of the cylindrical vessel =  Height of the cylinder =  Let the radius of the circular base be   The inner curved surface area of the cylindrical vessel =  Therefore, the radius of the base of the vessel is

H Harsh Kankaria
(i) Given, Rs 20 is the cost of painting  area of the inner curved surface of the cylinder.   Rs 2200 is the cost of painting area of the inner curved surface of the cylinder.   The inner curved surface area of the cylindrical vessel =

H Harsh Kankaria
Given, The lateral surface area of the cylinder =  Height of the cylinder =  The radius of the base is  (ii) We know, The volume of a cylinder =  Therefore, volume of the cylinder is

H Harsh Kankaria
Given, Lateral surface area of the cylinder =  Height of the cylinder =  (i) Let the radius of the base be  We know, The lateral surface area of a cylinder =  Therefore, the radius of the base is

H Harsh Kankaria
Given,  (i) The dimension of the rectangular base of the tin can =  Height of the can =   The volume of the tin can =  (ii) The radius of the circular base of the plastic cylinder =  Height of the cylinder =   Volume of the plastic cylinder =  Clearly, the plastic cylinder has more capacity than the rectangular tin can. The difference in capacity =