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Q : 9    A heap of wheat is in the form of a cone whose diameter is \small 10.5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.
 

Given, Height of the conical heap =   Base radius of the cone =  We know,  The volume of a cone =  The required volume of the cone formed =  Now, The slant height of the cone =  We know, the curved surface area of a cone =  The required area of the canvas to cover the heap  =   

7. A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained

Q : 8    If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained in Questions 7 and 8.
 

When a right-angled triangle is revolved about the perpendicular side, a cone is formed whose, Height of the cone = Length of the axis=  Base radius of the cone =  And, Slant height of the cone =  We know,  The volume of a cone =  The required volume of the cone formed =  Now, Ratio of the volumes of the two solids =  Therefore, the required ratio is 

Q : 7    A right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained.
 

When a right-angled triangle is revolved about the perpendicular side, a cone is formed whose, Height of the cone = Length of the axis=  Base radius of the cone =  And, Slant height of the cone =  We know,  The volume of a cone =  The required volume of the cone formed =  Therefore, the volume of the solid cone obtained is 

Q : 7    The volume of a right circular cone is \small 9856\hspace{1mm}cm^3. If the diameter of the base is 28 cm, find

             (iii) curved surface area of the cone
 

Given, a right circular cone. The radius of the base of the cone =  And Slant height of the cone =   (iii) We know, The curved surface area of a cone =  Required curved surface area= 

Q : 6    The volume of a right circular cone is \small 9856\hspace{1mm}cm^3. If the diameter of the base is 28 cm, find

            (ii) slant height of the cone 
 

Given, a right circular cone. The volume of the cone =  The radius of the base of the cone =  And the height of the cone =   (ii) We know, Slant height,  Therefore, the slant height of the cone is 

Q : 5    A conical pit of top diameter \small 3.5 m is 12 m deep. What is its capacity in kilolitres?

Given, Depth of the conical pit  =  The top radius of the conical pit =  We know, The volume of a right circular cone =   The volume of the conical pit =    Now,   The capacity of the pit =   

Q : 4    If the volume of a right circular cone of height 9 cm is \small 48\pi \hspace{1mm}cm^3, find the diameter of its base.
 

Given, Height of the cone =  Let the radius of the base of the cone be  We know, The volume of a right circular cone =    Therefore the diameter of the right circular cone is 

Q : 3    The height of a cone is 15 cm. If its volume is 1570 \small cm^3, find the radius of the base. (Use \small \pi =3.14

Given, Height of the cone =  Let the radius of the base of the cone be  We know, The volume of a right circular cone =   

Q : 2     Find the capacity in litres of a conical vessel with

             (ii) height 12 cm, slant height 13 cm 

Given, Height =  Slant height =  Radius =  We know, Volume of a right circular cone =   Volume of the vessel=   Required capacity of the vessel = 

Q : 2     Find the capacity in litres of a conical vessel with

            (i) radius 7 cm, slant height 25 cm

Given, Radius =  Slant height =  Height =  We know, Volume of a right circular cone =   Volume of the vessel=   Required capacity of the vessel = 

Q: 1    Find the volume of the right circular cone with:

            (ii) radius \small 3.5 cm, height 12 cm

Given, Radius =  Height =  We know, Volume of a right circular cone =   Required volume = 

Q : 1    Find the volume of the right circular cone with

            (i) radius 6 cm, height 7 cm

Given, Radius =  Height =  We know, Volume of a right circular cone =   Required volume =   
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