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Not an aromatic compound because the -electrons in the ring are not in a complete conjugation. And it is a non-planner structure.
The necessary conditions for any system to be aromatic are - The cyclic compound should be a planner  The complete(continuous) delocalisation of -electrons in the ring Follow the Huckel rule- it states that, the ring has (4n+2)-electrons, where n =integer(n = 0, 1, 2, 3....)
Benzene is a hybrid of various resonating structure. Each carbon of benzene is in  hybridisation. Two  hybrid orbitals of each carbon is overlapping with adjacent carbon atoms orbital resulting in six C-C sigma bonds all are in a hexagonal plane and remaining   orbital overlap with s-orbitals of hydrogen and form C-H sigma bonds. In benzene six C-H sigma bond presents. And the remaining...
The structure of the hex-2-ene is shown here- Now, the Geometrical, cis and trans isomers - Cis-isomer has a higher boiling point than trans-isomers due to more dipole-dipole interaction between the molecules. The cis-form is more polar than trans-form because it has a high dipole moment than trans-form. Trans-form is almost non-polar in nature.
Combustion means the reaction of the given compound with the dioxygen() gives  carbon dioxide, water molecule and produce some amount of heat.

Combustion means the reaction of the given compound with the dioxygen($O_2$) gives  carbon dioxide, water molecule and produce some amount of heat.

Combustion means the reaction of a compound with the dioxygen(). Combustion reaction of the Pentene-
Combustion means the reaction of a compound with the dioxygen()
In the process of ozonolysis, an ozonide, cyclic ring structure intermediate is formed, which undergoes cleavage to give the product. The parent compound produces pentan-3-one and propanal. So, the possible structure should be- Here in this above structure, right side Pent-3-one and the left-hand side propanal structure. Thus, by removing the ozone from ozonide we can get the parent alkene...
As per given data, compound A on ozonolysis give two moles of aldehyde, having molar mass 44u. It indicates that the compound has an identical structure around (both sides) a double bond. So, the possible general structure of A =  There are eight  sigma bonds, it  means eight Hydrogen atoms in the structure A. Also, three  bonds, it indicates the presence of four Carbon atom in A. Now, by...
In the process of ozonolysis, an ozonide, cyclic ring structure intermediate is formed, which undergoes cleavage to give the product. The compound A produce pentan-3-one and ethanal. So, the possible structure of A should be- Thus, by removing the ozone from ozonide we can get the parent alkene structure.
On ozonolysis of 1-Phenylbut-1-ene gives two product of aldehyde compound. one is aromatic in nature and other is aliphatic aldehyde. The IUPAC name of the compound is-(i) Benzaldehyde (ii)propanal
Ozonolysis of 2-Ethylbut-1-ene  gives two products one is keto compound and another is aldehyde. 2-Ethylbut-1-ene  + O3                                                                                    (i)                                                              (ii) aldehyde The IUPAC name of the compound (i) is Pentan-3-one and the name of the (ii) compound is methanal.
Ozonolysis of 3,4-Dimethylhept-3-ene , gives two product of keto-compounds. The ozone molecules attach at the double bond. The IUPAC name of the compound is -(i)  Butan-2-one (ii) Pentan-2-one
Ozonolysis of Pent-2-ene gives two product both are aldehyde compounds. In this process, the ozone molecules attached at double bond of the molecule and break it into two products The IUPAC name of the compounds-(i) ethanal (ii) propanal
the following isomers are possible with one double bond ; But-1-ene But-2-ene                  2-Methylprop-1-ene
The IUPAC name of the compound is- 4-ethylDeca-1, 4, 8-triene
The IUPAC name of the compound is- 5-(2-methyl propyl)-decane
The IUPAC name of the compound is  2-methylphenol
The IUPAC name of the compound is  4-phenylbut-1-ene
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