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Dissociation of K2SO4 is as follows :-                                     It is clear that 3 ions are produced, so the value of i will be 3. Molecular weight of K2SO4 = 2(39) + 1(32) + 4(16) = 174u.                                                  Putting all the values :-
We know that osmotic pressure :                                                      or                                                  We have been given the values of osmotic pressure, V, i and T. So the value of w can be found.                                                                                                                                                                  ...
We have been given that the water is in equilibrium with air at a pressure of 10 atm or 7600 mm of Hg.  So the partial pressure of oxygen :                                                              and partial pressure of nitrogen :                                                              Now, by Henry's Law :                                       For oxygen :                           ...
Firstly, we will find the no. of moles of the given compounds. No. of moles of benzene :                                                  and the no. of moles of toluene :                                                  . Now we will find mol fraction of both:-  Mole fraction of benzene :-                                                       and mole fraction of toluene :                     ...
it has negative deviation from the ideal solution.
For calculating partial vapour pressure we need to calculate mole fractions of components. So number of moles of liquid A :                                                          and  moles of liquid B :                                                         Mole fraction of A (xA)   :                                                        and mole fraction of B (xB)  :                     ...
We know that :             We are given value of P and k, so C can be found.                                       Hence solubility of methane in benzene is .
Firstly we will find number of moles of both water and glucose. Moles of glucose :                                                                           and moles of water :                                                                                 Now,                                               or                                        or                                       ...
Firstly we need to calculate molality in order to get vant's hoff factor. So moles of CH2FCOOH :                                                  We need to assume volume of solution to be nearly equal to 500 mL.         (as 500 g water is present) Now, we know that :             or                                            Now for dissociation constant :-                                     ...
Firstly we will find the Vant's Hoff factor the dissociation of given compound.                  So we can write,                                              or                                                                                                                        or                                                                       Putting values of Ka and C in the last...
We know that depression in freezing point of water will depend upon the degree of ionisation. The degree of ionisation will be highest in the case of trifluoroacetic acid as it is most acidic among all three. The order of degree of ionisation on the basis if acidic nature will be:-     Trifluoroacetic acid > Trichloroacetic acid > Acetic acid. So the depression in freezing point will be reverse...
Molar mass of benzoic acid = 7(12) + 6(1) + 2(16) = 122u. We are given with the molarity of solution.                                                    or                                                           or                                       So mass of benzoic acid :                                                                                               Hence the required...
We are given with molality of the solution, so we need to find the moles of Nalorphene. Molar mass of nalorphene =  19(12) + 21(1)  + 1(14) + 3(16)  =  311u. So moles of nalorphene :                                               Molality :                                                            or                                                        or                                     ...
Total mass of solution = Mass of aspirin + Mass of acetonitrile = 6.5 + 450 = 456.5 g. We know that :                             So,                                                  Thus the mass percentage of aspirin is
We are given,       The dissociation equation of CuS is given by :-                                         So, the equation becomes :-    or                                             or                                                      Thus maximum molarity of solution is   .
We know that, Molality :                                            So, for moles of solute we have :                                Thus,  molality :                                          Molality of Na+ ions is 4m.
Pentanol has both polar and non-polar groups so it is partially soluble in water.
Chloroform is a non-polar compound so it is insoluble in water.
Ethylene glycol is an organic compound but is polar in nature. Also, it can form H-bonds with water molecules, thus it is highly soluble in water.
Since the -OH group in formic acid (polar) can form H-bonds with water thus it is highly soluble in water.
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